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28u^2-29u+6=0
a = 28; b = -29; c = +6;
Δ = b2-4ac
Δ = -292-4·28·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-13}{2*28}=\frac{16}{56} =2/7 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+13}{2*28}=\frac{42}{56} =3/4 $
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